The DELETE JOIN
allows us to delete data from multiple tables using a join. Often we will want o connect multiple tables, then delete rows. In this article, we will learn how to use DELETE JOIN
in MySQL.
The basic syntax of DELETE JOIN is as follows:
DELETE [table1], [table2]
FROM [table1]
JOIN [table2] ON key1 = key2
WHERE [condition]
This syntax will allow us to delete multiple rows based on the join and conditions we supply.
We will be using docker in this article, but feel free to install your database locally instead. Once you have docker installed, create a new file called docker-compose.yml
and add the following.
version: '3'
services:
db:
image: mysql:latest
container_name: db
environment:
MYSQL_ROOT_PASSWORD: root_pass
MYSQL_DATABASE: app_db
MYSQL_USER: db_user
MYSQL_PASSWORD: db_user_pass
ports:
- "6033:3306"
volumes:
- dbdata:/var/lib/mysql
phpmyadmin:
image: phpmyadmin/phpmyadmin
container_name: pma
links:
- db
environment:
PMA_HOST: db
PMA_PORT: 3306
PMA_ARBITRARY: 1
restart: always
ports:
- 8081:80
volumes:
dbdata:
Next, run docker-compose up
.
Now, navigate to http://localhost:8081/
to access phpMyAdmin. Then log in with the username root
and pass root_pass
.
Click the SQL tab and you are ready to go.
In this article, we will need some data to work with. We will be using the sample db provided here: https://dev.mysql.com/doc/employee/en/. However, we will only enter what we need rather than import the whole db.
With the SQL tab open (or your own sql cli going), let's first create our DB and select it.
create DATABASE if not EXISTS sakila;
USE sakila;
CREATE TABLE employees (
emp_no INT NOT NULL,
birth_date DATE NOT NULL,
first_name VARCHAR(14) NOT NULL,
last_name VARCHAR(16) NOT NULL,
gender ENUM ('M','F') NOT NULL,
hire_date DATE NOT NULL,
PRIMARY KEY (emp_no)
);
CREATE TABLE salaries (
emp_no INT NOT NULL,
salary INT NOT NULL,
from_date DATE NOT NULL,
to_date DATE NOT NULL,
FOREIGN KEY (emp_no) REFERENCES employees (emp_no) ON DELETE CASCADE,
PRIMARY KEY (emp_no, from_date)
);
Now, let's enter a few rows
INSERT INTO employees VALUES (10001,'1953-09-02','Georgi','Facello','M','1986-06-26'),
(10002,'1964-06-02','Bezalel','Simmel','F','1985-11-21'),
(10003,'1959-12-03','Parto','Bamford','M','1986-08-28'),
(10004,'1954-05-01','Chirstian','Koblick','M','1986-12-01'),
(10005,'1955-01-21','Kyoichi','Maliniak','M','1989-09-12'),
(10006,'1953-04-20','Anneke','Preusig','F','1989-06-02'),
(10007,'1957-05-23','Tzvetan','Zielinski','F','1989-02-10'),
(10008,'1958-02-19','Saniya','Kalloufi','M','1994-09-15'),
(10009,'1952-04-19','Sumant','Peac','F','1985-02-18'),
(10010,'1963-06-01','Duangkaew','Piveteau','F','1989-08-24'),
(10011,'1953-11-07','Mary','Sluis','F','1990-01-22'),
(10012,'1960-10-04','Patricio','Bridgland','M','1992-12-18'),
(10013,'1963-06-07','Eberhardt','Terkki','M','1985-10-20'),
(10014,'1956-02-12','Berni','Genin','M','1987-03-11'),
(10015,'1959-08-19','Guoxiang','Nooteboom','M','1987-07-02'),
(10016,'1961-05-02','Kazuhito','Cappelletti','M','1995-01-27'),
(10017,'1958-07-06','Cristinel','Bouloucos','F','1993-08-03'),
(10018,'1954-06-19','Kazuhide','Peha','F','1987-04-03'),
(10019,'1953-01-23','Lillian','Haddadi','M','1999-04-30'),
(10020,'1952-12-24','Mayuko','Warwick','M','1991-01-26');
INSERT INTO salaries VALUES (10001,60117,'1986-06-26','1987-06-26'),
(10002,62102,'1987-06-26','1988-06-25'),
(10003,66074,'1988-06-25','1989-06-25'),
(10004,66596,'1989-06-25','1990-06-25'),
(10005,66961,'1990-06-25','1991-06-25'),
(10006,71046,'1991-06-25','1992-06-24'),
(10007,74333,'1992-06-24','1993-06-24'),
(10008,75286,'1993-06-24','1994-06-24'),
(10009,75994,'1994-06-24','1995-06-24'),
(10010,76884,'1995-06-24','1996-06-23'),
(10011,80013,'1996-06-23','1997-06-23'),
(10012,81025,'1997-06-23','1998-06-23'),
(10013,81097,'1998-06-23','1999-06-23');
Let’s do an example where we select multiple employees, joined with their salaries. We will filter based on salary then delete. This will remove all employee rows and salary rows that meet our search.
First, let’s select to see all the rows we will delete.
SELECT *
FROM employees AS e
JOIN salaries AS s on e.emp_no = s.emp_no
WHERE s.salary < 70000;
emp_no | birth_date | first_name | last_name | gender | hire_date | emp_no | salary | from_date | to_date |
---|---|---|---|---|---|---|---|---|---|
10001 | 1953-09-02 | Georgi | Facello | M | 1986-06-26 | 10001 | 60117 | 1986-06-26 | 1987-06-26 |
10001 | 1953-09-02 | Georgi | Facello | M | 1986-06-26 | 10001 | 62102 | 1987-06-26 | 1988-06-25 |
10001 | 1953-09-02 | Georgi | Facello | M | 1986-06-26 | 10001 | 66074 | 1988-06-25 | 1989-06-25 |
10001 | 1953-09-02 | Georgi | Facello | M | 1986-06-26 | 10001 | 66596 | 1989-06-25 | 1990-06-25 |
10001 | 1953-09-02 | Georgi | Facello | M | 1986-06-26 | 10001 | 66961 | 1990-06-25 | 1991-06-25 |
DELETE employees
FROM employees
JOIN salaries AS s on employees.emp_no = s.emp_no
WHERE s.salary < 70000;
Since we specify employee
after DELETE
this will delete the employee rows based on our join condition. On thing to notice is we have ON DELETE CASCADE
on the salary
table, thus when we delete the linked employee, the salary row will also be deleted.
SELECT * FROM salaries s;
emp_no | salary | from_date | to_date |
---|---|---|---|
10006 | 71046 | 1991-06-25 | 1992-06-24 |
10007 | 74333 | 1992-06-24 | 1993-06-24 |
10008 | 75286 | 1993-06-24 | 1994-06-24 |
10009 | 75994 | 1994-06-24 | 1995-06-24 |
10010 | 76884 | 1995-06-24 | 1996-06-23 |
10011 | 80013 | 1996-06-23 | 1997-06-23 |
10012 | 81025 | 1997-06-23 | 1998-06-23 |
10013 | 81097 | 1998-06-23 | 1999-06-23 |